How to solve 3/7-13/35

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/7-13/35 | Equatix

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$$3/7-13/35$$

$\frac{2}{35}\approx 0.057142857$

Least common multiple of $7$ and $35$ is $35$. Convert $\frac{3}{7}$ and $\frac{13}{35}$ to fractions with denominator $35$.

$$\frac{15}{35}-\frac{13}{35}$$

Since $\frac{15}{35}$ and $\frac{13}{35}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{15-13}{35}$$

Subtract $13$ from $15$ to get $2$.

$$\frac{2}{35}$$

$\frac{2}{5 \cdot 7} = 0.05714285714285714$