1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/8+4/3 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$3/8+4/3$$

$\frac{41}{24}\approx 1.708333333$

Least common multiple of $8$ and $3$ is $24$. Convert $\frac{3}{8}$ and $\frac{4}{3}$ to fractions with denominator $24$.

$$\frac{9}{24}+\frac{32}{24}$$

Since $\frac{9}{24}$ and $\frac{32}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{9+32}{24}$$

Add $9$ and $32$ to get $41$.

$$\frac{41}{24}$$

$\frac{41}{2 ^ {3} \cdot 3} = 1\frac{17}{24} = 1.7083333333333333$