How to solve 3/8+7/72

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/8+7/72 | Equatix

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$$3/8+7/72$$

$\frac{17}{36}\approx 0.472222222$

Least common multiple of $8$ and $72$ is $72$. Convert $\frac{3}{8}$ and $\frac{7}{72}$ to fractions with denominator $72$.

$$\frac{27}{72}+\frac{7}{72}$$

Since $\frac{27}{72}$ and $\frac{7}{72}$ have the same denominator, add them by adding their numerators.

$$\frac{27+7}{72}$$

Add $27$ and $7$ to get $34$.

$$\frac{34}{72}$$

Reduce the fraction $\frac{34}{72}$ to lowest terms by extracting and canceling out $2$.

$$\frac{17}{36}$$

$\frac{17}{2 ^ {2} \cdot 3 ^ {2}} = 0.4722222222222222$