Solve for \(f\) in \(3e+f=5\).
Solve for \(f\).
\[3e+f=5\]
Subtract \(3e\) from both sides.
\[f=5-3e\]
\[f=5-3e\]
Substitute \(f=5-3e\) into \(e-f=-1\).
Start with the original equation.
\[e-f=-1\]
Let \(f=5-3e\).
\[e-5+3e=-1\]
Simplify.
\[4e-5=-1\]
\[4e-5=-1\]
Since \(4e-5=-1\) is not true, this is an inconsistent system.
