Question

$$3=4\times5^{2}+3\times4^{-1}-3^{-2}$$

Answer

[No Solution]

Solution


Simplify  \({5}^{2}\)  to  \(25\).
\[3=4\times 25+3\times {4}^{-1}-{3}^{-2}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[3=4\times 25+3\times \frac{1}{4}-{3}^{-2}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[3=4\times 25+3\times \frac{1}{4}-\frac{1}{{3}^{2}}\]
Simplify  \({3}^{2}\)  to  \(9\).
\[3=4\times 25+3\times \frac{1}{4}-\frac{1}{9}\]
Simplify  \(4\times 25\)  to  \(100\).
\[3=100+3\times \frac{1}{4}-\frac{1}{9}\]
Simplify  \(3\times \frac{1}{4}\)  to  \(\frac{3}{4}\).
\[3=100+\frac{3}{4}-\frac{1}{9}\]
Simplify  \(100+\frac{3}{4}-\frac{1}{9}\)  to  \(\frac{3623}{36}\).
\[3=\frac{3623}{36}\]
Since \(3=\frac{3623}{36}\) is false, there is no solution.
No Solution