$$3\frac{1}{3}; \frac{1}{2}+2\div[2\times\{2-(2-\frac{1}{5})\}]$$
$\frac{20}{3}\approx 6.666666667$
$$\frac{9+1}{3}\times \frac{1}{2}+\frac{2}{2\left(2-\left(2-\frac{1}{5}\right)\right)}$$
$$\frac{10}{3}\times \frac{1}{2}+\frac{2}{2\left(2-\left(2-\frac{1}{5}\right)\right)}$$
$$\frac{10\times 1}{3\times 2}+\frac{2}{2\left(2-\left(2-\frac{1}{5}\right)\right)}$$
$$\frac{10}{6}+\frac{2}{2\left(2-\left(2-\frac{1}{5}\right)\right)}$$
$$\frac{5}{3}+\frac{2}{2\left(2-\left(2-\frac{1}{5}\right)\right)}$$
$$\frac{5}{3}+\frac{2}{2\left(2-\left(\frac{10}{5}-\frac{1}{5}\right)\right)}$$
$$\frac{5}{3}+\frac{2}{2\left(2-\frac{10-1}{5}\right)}$$
$$\frac{5}{3}+\frac{2}{2\left(2-\frac{9}{5}\right)}$$
$$\frac{5}{3}+\frac{2}{2\left(\frac{10}{5}-\frac{9}{5}\right)}$$
$$\frac{5}{3}+\frac{2}{2\times \frac{10-9}{5}}$$
$$\frac{5}{3}+\frac{2}{2\times \frac{1}{5}}$$
$$\frac{5}{3}+\frac{2}{\frac{2}{5}}$$
$$\frac{5}{3}+2\times \frac{5}{2}$$
$$\frac{5}{3}+5$$
$$\frac{5}{3}+\frac{15}{3}$$
$$\frac{5+15}{3}$$
$$\frac{20}{3}$$
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$\frac{2 ^ {2} \cdot 5}{3} = 6\frac{2}{3} = 6.666666666666667$
