How to solve 3 1/5 - 2 7/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 1/5 - 2 7/5 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3\frac{1}{5}-2\frac{7}{5}$$

Evaluate

$-\frac{1}{5}=-0.2$

Solution Steps

Multiply $3$ and $5$ to get $15$.

$$\frac{15+1}{5}-\frac{2\times 5+7}{5}$$

Add $15$ and $1$ to get $16$.

$$\frac{16}{5}-\frac{2\times 5+7}{5}$$

Multiply $2$ and $5$ to get $10$.

$$\frac{16}{5}-\frac{10+7}{5}$$

Add $10$ and $7$ to get $17$.

$$\frac{16}{5}-\frac{17}{5}$$

Since $\frac{16}{5}$ and $\frac{17}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-17}{5}$$

Subtract $17$ from $16$ to get $-1$.

$$-\frac{1}{5}$$

Show Solution

Factor

$-\frac{1}{5} = -0.2$

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