1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$3 \frac { 3 } { 4 } - \frac { 1 } { 3 }$$

$\frac{41}{12}\approx 3.416666667$

Multiply $3$ and $4$ to get $12$.

$$\frac{12+3}{4}-\frac{1}{3}$$

Add $12$ and $3$ to get $15$.

$$\frac{15}{4}-\frac{1}{3}$$

Least common multiple of $4$ and $3$ is $12$. Convert $\frac{15}{4}$ and $\frac{1}{3}$ to fractions with denominator $12$.

$$\frac{45}{12}-\frac{4}{12}$$

Since $\frac{45}{12}$ and $\frac{4}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{45-4}{12}$$

Subtract $4$ from $45$ to get $41$.

$$\frac{41}{12}$$

$\frac{41}{2 ^ {2} \cdot 3} = 3\frac{5}{12} = 3.4166666666666665$