$$3\frac{3(y-5)}{4}-4y=3-\frac{(y-3)}{2}$$
$y = -\frac{63}{5} = -12\frac{3}{5} = -12.6$
$$3\times 3\left(y-5\right)-16y=12-2\left(y-3\right)$$
$$9\left(y-5\right)-16y=12-2\left(y-3\right)$$
$$9y-45-16y=12-2\left(y-3\right)$$
$$-7y-45=12-2\left(y-3\right)$$
$$-7y-45=12-2y+6$$
$$-7y-45=18-2y$$
$$-7y-45+2y=18$$
$$-5y-45=18$$
$$-5y=18+45$$
$$-5y=63$$
$$y=\frac{63}{-5}$$
$$y=-\frac{63}{5}$$
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