$$3\frac{5}{12}\cdot(4\frac{5}{6}-\frac{1}{2}+1\frac{1}{8})$$
$\frac{5371}{288}\approx 18.649305556$
$$\frac{36+5}{12}\left(\frac{4\times 6+5}{6}-\frac{1}{2}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{4\times 6+5}{6}-\frac{1}{2}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{24+5}{6}-\frac{1}{2}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{29}{6}-\frac{1}{2}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{29}{6}-\frac{3}{6}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{29-3}{6}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{26}{6}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{13}{3}+\frac{1\times 8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{13}{3}+\frac{8+1}{8}\right)$$
$$\frac{41}{12}\left(\frac{13}{3}+\frac{9}{8}\right)$$
$$\frac{41}{12}\left(\frac{104}{24}+\frac{27}{24}\right)$$
$$\frac{41}{12}\times \frac{104+27}{24}$$
$$\frac{41}{12}\times \frac{131}{24}$$
$$\frac{41\times 131}{12\times 24}$$
$$\frac{5371}{288}$$
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$\frac{41 \cdot 131}{2 ^ {5} \cdot 3 ^ {2}} = 18\frac{187}{288} = 18.649305555555557$
