$$3\frac{5}{12}\cdot(4\frac{5}{6}-\frac{1}{2}+2\frac{7}{8})$$
$\frac{7093}{288}\approx 24.628472222$
$$\frac{36+5}{12}\left(\frac{4\times 6+5}{6}-\frac{1}{2}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{4\times 6+5}{6}-\frac{1}{2}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{24+5}{6}-\frac{1}{2}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{29}{6}-\frac{1}{2}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{29}{6}-\frac{3}{6}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{29-3}{6}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{26}{6}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{13}{3}+\frac{2\times 8+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{13}{3}+\frac{16+7}{8}\right)$$
$$\frac{41}{12}\left(\frac{13}{3}+\frac{23}{8}\right)$$
$$\frac{41}{12}\left(\frac{104}{24}+\frac{69}{24}\right)$$
$$\frac{41}{12}\times \frac{104+69}{24}$$
$$\frac{41}{12}\times \frac{173}{24}$$
$$\frac{41\times 173}{12\times 24}$$
$$\frac{7093}{288}$$
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$\frac{41 \cdot 173}{2 ^ {5} \cdot 3 ^ {2}} = 24\frac{181}{288} = 24.62847222222222$
