Solve 3-2-(4-(6+4)-8+(1+3)-8)+4 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3-2-(4-(6+4)-8+(1+3)-8)+4$$

Evaluate

$23$

Solution Steps

Subtract $2$ from $3$ to get $1$.

$$1-\left(4-\left(6+4\right)-8+1+3-8\right)+4$$

Add $6$ and $4$ to get $10$.

$$1-\left(4-10-8+1+3-8\right)+4$$

Subtract $10$ from $4$ to get $-6$.

$$1-\left(-6-8+1+3-8\right)+4$$

Subtract $8$ from $-6$ to get $-14$.

$$1-\left(-14+1+3-8\right)+4$$

Add $-14$ and $1$ to get $-13$.

$$1-\left(-13+3-8\right)+4$$

Add $-13$ and $3$ to get $-10$.

$$1-\left(-10-8\right)+4$$

Subtract $8$ from $-10$ to get $-18$.

$$1-\left(-18\right)+4$$

The opposite of $-18$ is $18$.

$$1+18+4$$

Add $1$ and $18$ to get $19$.

$$19+4$$

Add $19$ and $4$ to get $23$.

$$23$$

Factor

$23$