How to solve 3-6x=1/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3-6x=1/2 | Equatix

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$$3-6x=1/2$$

$x=\frac{5}{12}\approx 0.416666667$

Subtract $3$ from both sides.

$$-6x=\frac{1}{2}-3$$

Convert $3$ to fraction $\frac{6}{2}$.

$$-6x=\frac{1}{2}-\frac{6}{2}$$

Since $\frac{1}{2}$ and $\frac{6}{2}$ have the same denominator, subtract them by subtracting their numerators.

$$-6x=\frac{1-6}{2}$$

Subtract $6$ from $1$ to get $-5$.

$$-6x=-\frac{5}{2}$$

Divide both sides by $-6$.

$$x=\frac{-\frac{5}{2}}{-6}$$

Express $\frac{-\frac{5}{2}}{-6}$ as a single fraction.

$$x=\frac{-5}{2\left(-6\right)}$$

Multiply $2$ and $-6$ to get $-12$.

$$x=\frac{-5}{-12}$$

Fraction $\frac{-5}{-12}$ can be simplified to $\frac{5}{12}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{5}{12}$$