$$3 - \frac { 2 y } { 5 } = \frac { 7 } { 15 }$$
$y = \frac{19}{3} = 6\frac{1}{3} \approx 6.333333333$
$$45-3\times 2y=7$$
$$45-6y=7$$
$$-6y=7-45$$
$$-6y=-38$$
$$y=\frac{-38}{-6}$$
$$y=\frac{19}{3}$$
Show Solution
Hide Solution
