How to solve 2y +3 3+ 4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2y +3 3+ 4 | Equatix

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Question

$$3 - \frac { 2 y + 3 } { 4 } + \frac { y - 5 } { 6 } = 0$$

Solve for y

$y = \frac{17}{4} = 4\frac{1}{4} = 4.25$

Steps for Solving Linear Equation

Multiply both sides of the equation by $12$, the least common multiple of $4,6$.

$$36-3\left(2y+3\right)+2\left(y-5\right)=0$$

Use the distributive property to multiply $-3$ by $2y+3$.

$$36-6y-9+2\left(y-5\right)=0$$

Subtract $9$ from $36$ to get $27$.

$$27-6y+2\left(y-5\right)=0$$

Use the distributive property to multiply $2$ by $y-5$.

$$27-6y+2y-10=0$$

Combine $-6y$ and $2y$ to get $-4y$.

$$27-4y-10=0$$

Subtract $10$ from $27$ to get $17$.

$$17-4y=0$$

Subtract $17$ from both sides. Anything subtracted from zero gives its negation.

$$-4y=-17$$

Divide both sides by $-4$.

$$y=\frac{-17}{-4}$$

Fraction $\frac{-17}{-4}$ can be simplified to $\frac{17}{4}$ by removing the negative sign from both the numerator and the denominator.

$$y=\frac{17}{4}$$

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