How to solve 3 - (2y)/5 = 7/15

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 - (2y)/5 = 7/15 | Equatix

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$$3-\frac{2y}{5}=\frac{7}{15}$$

$y = \frac{19}{3} = 6\frac{1}{3} \approx 6.333333333$

Multiply both sides of the equation by $15$, the least common multiple of $5,15$.

$$45-3\times 2y=7$$

Multiply $-3$ and $2$ to get $-6$.

$$45-6y=7$$

Subtract $45$ from both sides.

$$-6y=7-45$$

Subtract $45$ from $7$ to get $-38$.

$$-6y=-38$$

Divide both sides by $-6$.

$$y=\frac{-38}{-6}$$

Reduce the fraction $\frac{-38}{-6}$ to lowest terms by extracting and canceling out $-2$.

$$y=\frac{19}{3}$$