$$3-\frac{7y+2}{5}=\frac{6y-5}{11}$$
$y = \frac{168}{107} = 1\frac{61}{107} \approx 1.570093458$
$$165-11\left(7y+2\right)=5\left(6y-5\right)$$
$$165-77y-22=5\left(6y-5\right)$$
$$143-77y=5\left(6y-5\right)$$
$$143-77y=30y-25$$
$$143-77y-30y=-25$$
$$143-107y=-25$$
$$-107y=-25-143$$
$$-107y=-168$$
$$y=\frac{-168}{-107}$$
$$y=\frac{168}{107}$$
Show Solution
Hide Solution