How to solve 3-((-1+-5)-12)=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3-((-1+-5)-12)= | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3-((-1+-5)-12)=$$

Evaluate

$21$

Solution Steps

Subtract $5$ from $-1$ to get $-6$.

$$3-\left(-6-12\right)$$

Subtract $12$ from $-6$ to get $-18$.

$$3-\left(-18\right)$$

The opposite of $-18$ is $18$.

$$3+18$$

Add $3$ and $18$ to get $21$.

$$21$$

Show Solution

Factor

$3\times 7$

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