How to solve 3(1-x) < 2(x+4)

Q: How to solve 3(1-x) < 2(x+4)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(1-x) < 2(x+4) | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(1-x) < 2(x+4)$$

Solve for x

$x>-1$

Solution Steps

Use the distributive property to multiply $3$ by $1-x$.

$$3-3x<2\left(x+4\right)$$

Use the distributive property to multiply $2$ by $x+4$.

$$3-3x<2x+8$$

Subtract $2x$ from both sides.

$$3-3x-2x<8$$

Combine $-3x$ and $-2x$ to get $-5x$.

$$3-5x<8$$

Subtract $3$ from both sides.

$$-5x<8-3$$

Subtract $3$ from $8$ to get $5$.

$$-5x<5$$

Divide both sides by $-5$. Since $-5$ is negative, the inequality direction is changed.

$$x>\frac{5}{-5}$$

Divide $5$ by $-5$ to get $-1$.

$$x>-1$$

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