Solve 3(24 - 1) + 2(4 + 3) + 7 = 0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(24-1)+2(4+3)+7=0$$

Verify

$\text{false}$

Solution Steps

Subtract $1$ from $24$ to get $23$.

$$3\times 23+2\left(4+3\right)+7=0$$

Multiply $3$ and $23$ to get $69$.

$$69+2\left(4+3\right)+7=0$$

Add $4$ and $3$ to get $7$.

$$69+2\times 7+7=0$$

Multiply $2$ and $7$ to get $14$.

$$69+14+7=0$$

Add $69$ and $14$ to get $83$.

$$83+7=0$$

Add $83$ and $7$ to get $90$.

$$90=0$$

Compare $90$ and $0$.

$$\text{false}$$