How to solve 3(2x-3)=4(2x+4)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(2x-3)=4(2x+4) | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(2x-3)=4(2x+4)$$

Solve for x

$x = -\frac{25}{2} = -12\frac{1}{2} = -12.5$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $2x-3$.

$$6x-9=4\left(2x+4\right)$$

Use the distributive property to multiply $4$ by $2x+4$.

$$6x-9=8x+16$$

Subtract $8x$ from both sides.

$$6x-9-8x=16$$

Combine $6x$ and $-8x$ to get $-2x$.

$$-2x-9=16$$

Add $9$ to both sides.

$$-2x=16+9$$

Add $16$ and $9$ to get $25$.

$$-2x=25$$

Divide both sides by $-2$.

$$x=\frac{25}{-2}$$

Fraction $\frac{25}{-2}$ can be rewritten as $-\frac{25}{2}$ by extracting the negative sign.

$$x=-\frac{25}{2}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Steps for Solving Linear Equation