How to solve 3(2x + 4) = 64

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(2x + 4) = 64 | Equatix

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Question

$$3(2x+4)=64$$

Solve for x

$x = \frac{26}{3} = 8\frac{2}{3} \approx 8.666666667$

Steps for Solving Linear Equation

Divide both sides by $3$.

$$2x+4=\frac{64}{3}$$

Subtract $4$ from both sides.

$$2x=\frac{64}{3}-4$$

Convert $4$ to fraction $\frac{12}{3}$.

$$2x=\frac{64}{3}-\frac{12}{3}$$

Since $\frac{64}{3}$ and $\frac{12}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$2x=\frac{64-12}{3}$$

Subtract $12$ from $64$ to get $52$.

$$2x=\frac{52}{3}$$

Divide both sides by $2$.

$$x=\frac{\frac{52}{3}}{2}$$

Express $\frac{\frac{52}{3}}{2}$ as a single fraction.

$$x=\frac{52}{3\times 2}$$

Multiply $3$ and $2$ to get $6$.

$$x=\frac{52}{6}$$

Reduce the fraction $\frac{52}{6}$ to lowest terms by extracting and canceling out $2$.

$$x=\frac{26}{3}$$

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