$$3(2y-1)+2(y+3)+7=0$$
$y = -\frac{5}{4} = -1\frac{1}{4} = -1.25$
$$6y-3+2\left(y+3\right)+7=0$$
$$6y-3+2y+6+7=0$$
$$8y-3+6+7=0$$
$$8y+3+7=0$$
$$8y+10=0$$
$$8y=-10$$
$$y=\frac{-10}{8}$$
$$y=-\frac{5}{4}$$
Show Solution
Hide Solution