$$3(5-y)=4(3y+2)+27$$
$y = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$
$$15-3y=4\left(3y+2\right)+27$$
$$15-3y=12y+8+27$$
$$15-3y=12y+35$$
$$15-3y-12y=35$$
$$15-15y=35$$
$$-15y=35-15$$
$$-15y=20$$
$$y=\frac{20}{-15}$$
$$y=-\frac{4}{3}$$
Show Solution
Hide Solution