Solve 3(5z - 7) - 2(9z - 11) = 4(8z - 13) - 17 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(5z-7)-2(9z-11)=4(8z-13)-17$$

Solve for z

$z=2$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $5z-7$.

$$15z-21-2\left(9z-11\right)=4\left(8z-13\right)-17$$

Use the distributive property to multiply $-2$ by $9z-11$.

$$15z-21-18z+22=4\left(8z-13\right)-17$$

Combine $15z$ and $-18z$ to get $-3z$.

$$-3z-21+22=4\left(8z-13\right)-17$$

Add $-21$ and $22$ to get $1$.

$$-3z+1=4\left(8z-13\right)-17$$

Use the distributive property to multiply $4$ by $8z-13$.

$$-3z+1=32z-52-17$$

Subtract $17$ from $-52$ to get $-69$.

$$-3z+1=32z-69$$

Subtract $32z$ from both sides.

$$-3z+1-32z=-69$$

Combine $-3z$ and $-32z$ to get $-35z$.

$$-35z+1=-69$$

Subtract $1$ from both sides.

$$-35z=-69-1$$

Subtract $1$ from $-69$ to get $-70$.

$$-35z=-70$$

Divide both sides by $-35$.

$$z=\frac{-70}{-35}$$

Divide $-70$ by $-35$ to get $2$.

$$z=2$$