Question

$$3 ( 6 a - 7 ) - 2 ( 4 a - 9 ) = 4 ( 5 a - 11 ) - 19$$

Answer

x=(4*(5*a-11)-19+2*(4*a-9))/(3*IM*(6*a-7))

Solution


Remove parentheses.
\[x\imath \times 3(6a-7)-2(4a-9)=4(5a-11)-19\]
Regroup terms.
\[3\imath x(6a-7)-2(4a-9)=4(5a-11)-19\]
Regroup terms.
\[-2(4a-9)+3\imath x(6a-7)=4(5a-11)-19\]
Add \(2(4a-9)\) to both sides.
\[3\imath x(6a-7)=4(5a-11)-19+2(4a-9)\]
Divide both sides by \(3\).
\[\imath x(6a-7)=\frac{4(5a-11)-19+2(4a-9)}{3}\]
Divide both sides by \(\imath \).
\[x(6a-7)=\frac{\frac{4(5a-11)-19+2(4a-9)}{3}}{\imath }\]
Simplify  \(\frac{\frac{4(5a-11)-19+2(4a-9)}{3}}{\imath }\)  to  \(\frac{4(5a-11)-19+2(4a-9)}{3\imath }\).
\[x(6a-7)=\frac{4(5a-11)-19+2(4a-9)}{3\imath }\]
Divide both sides by \(6a-7\).
\[x=\frac{\frac{4(5a-11)-19+2(4a-9)}{3\imath }}{6a-7}\]
Simplify  \(\frac{\frac{4(5a-11)-19+2(4a-9)}{3\imath }}{6a-7}\)  to  \(\frac{4(5a-11)-19+2(4a-9)}{3\imath (6a-7)}\).
\[x=\frac{4(5a-11)-19+2(4a-9)}{3\imath (6a-7)}\]