$$3(a+b)^{2}-10(a+b)+8$$
$\left(a+b-2\right)\left(3a+3b-4\right)$
$$3\left(a^{2}+2ab+b^{2}\right)-10\left(a+b\right)+8$$
$$3a^{2}+6ab+3b^{2}-10\left(a+b\right)+8$$
$$3a^{2}+6ab+3b^{2}-10a-10b+8$$
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$3a^{2}+6ab-10a+3b^{2}-10b+8$
