$$3(a+b)^{2}-2a-2b-8$$
$\left(a+b-2\right)\left(3a+3b+4\right)$
$$3\left(a^{2}+2ab+b^{2}\right)-2a-2b-8$$
$$3a^{2}+6ab+3b^{2}-2a-2b-8$$
Show Solution
Hide Solution
$3a^{2}+6ab-2a+3b^{2}-2b-8$