$$3(a^{2}+2a+1)+4[a^{2}-2(2a-2)]$$
$7a^{2}-10a+19$
$$3a^{2}+6a+3+4\left(a^{2}-2\left(2a-2\right)\right)$$
$$3a^{2}+6a+3+4\left(a^{2}-4a+4\right)$$
$$3a^{2}+6a+3+4a^{2}-16a+16$$
$$7a^{2}+6a+3-16a+16$$
$$7a^{2}-10a+3+16$$
$$7a^{2}-10a+19$$
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