Solve 3( 29 15 )-( 1 13 )= boxed 7 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(\frac{29}{15})-(\frac{1}{13})=\boxed{7}$$

Verify

$\text{false}$

Solution Steps

Express $3\times \frac{29}{15}$ as a single fraction.

$$\frac{3\times 29}{15}-\frac{1}{13}=7$$

Multiply $3$ and $29$ to get $87$.

$$\frac{87}{15}-\frac{1}{13}=7$$

Reduce the fraction $\frac{87}{15}$ to lowest terms by extracting and canceling out $3$.

$$\frac{29}{5}-\frac{1}{13}=7$$

Least common multiple of $5$ and $13$ is $65$. Convert $\frac{29}{5}$ and $\frac{1}{13}$ to fractions with denominator $65$.

$$\frac{377}{65}-\frac{5}{65}=7$$

Since $\frac{377}{65}$ and $\frac{5}{65}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{377-5}{65}=7$$

Subtract $5$ from $377$ to get $372$.

$$\frac{372}{65}=7$$

Convert $7$ to fraction $\frac{455}{65}$.

$$\frac{372}{65}=\frac{455}{65}$$

Compare $\frac{372}{65}$ and $\frac{455}{65}$.

$$\text{false}$$