Solve 3(k - 3) = 5(2k - 1) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(k-3)=5(2k-1)$$

Solve for k

$k=-\frac{4}{7}\approx -0.571428571$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $k-3$.

$$3k-9=5\left(2k-1\right)$$

Use the distributive property to multiply $5$ by $2k-1$.

$$3k-9=10k-5$$

Subtract $10k$ from both sides.

$$3k-9-10k=-5$$

Combine $3k$ and $-10k$ to get $-7k$.

$$-7k-9=-5$$

Add $9$ to both sides.

$$-7k=-5+9$$

Add $-5$ and $9$ to get $4$.

$$-7k=4$$

Divide both sides by $-7$.

$$k=\frac{4}{-7}$$

Fraction $\frac{4}{-7}$ can be rewritten as $-\frac{4}{7}$ by extracting the negative sign.

$$k=-\frac{4}{7}$$