$$3(-\frac{1}{3})^{2}-2(-\frac{1}{3})-1$$
$0$
$$3\times \frac{1}{9}-2\left(-\frac{1}{3}\right)-1$$
$$\frac{3}{9}-2\left(-\frac{1}{3}\right)-1$$
$$\frac{1}{3}-2\left(-\frac{1}{3}\right)-1$$
$$\frac{1}{3}-\frac{2\left(-1\right)}{3}-1$$
$$\frac{1}{3}-\frac{-2}{3}-1$$
$$\frac{1}{3}-\left(-\frac{2}{3}\right)-1$$
$$\frac{1}{3}+\frac{2}{3}-1$$
$$\frac{1+2}{3}-1$$
$$\frac{3}{3}-1$$
$$1-1$$
$$0$$
Show Solution
Hide Solution
