$$3(n-4)+2(4n-5)=5(n+2)+16$$
$n=8$
$$3n-12+2\left(4n-5\right)=5\left(n+2\right)+16$$
$$3n-12+8n-10=5\left(n+2\right)+16$$
$$11n-12-10=5\left(n+2\right)+16$$
$$11n-22=5\left(n+2\right)+16$$
$$11n-22=5n+10+16$$
$$11n-22=5n+26$$
$$11n-22-5n=26$$
$$6n-22=26$$
$$6n=26+22$$
$$6n=48$$
$$n=\frac{48}{6}$$
$$n=8$$
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