How to solve 3(x-1) > x-7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(x-1) > x-7 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(x-1) > x-7$$

Solve for x

$x>-2$

Solution Steps

Use the distributive property to multiply $3$ by $x-1$.

$$3x-3>x-7$$

Subtract $x$ from both sides.

$$3x-3-x>-7$$

Combine $3x$ and $-x$ to get $2x$.

$$2x-3>-7$$

Add $3$ to both sides.

$$2x>-7+3$$

Add $-7$ and $3$ to get $-4$.

$$2x>-4$$

Divide both sides by $2$. Since $2$ is positive, the inequality direction remains the same.

$$x>\frac{-4}{2}$$

Divide $-4$ by $2$ to get $-2$.

$$x>-2$$

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Question

Solve for x

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