How to solve 3(x-4)+6=2(x+2)-2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(x-4)+6=2(x+2)-2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(x-4)+6=2(x+2)-2$$

Solve for x

$x=8$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $x-4$.

$$3x-12+6=2\left(x+2\right)-2$$

Add $-12$ and $6$ to get $-6$.

$$3x-6=2\left(x+2\right)-2$$

Use the distributive property to multiply $2$ by $x+2$.

$$3x-6=2x+4-2$$

Subtract $2$ from $4$ to get $2$.

$$3x-6=2x+2$$

Subtract $2x$ from both sides.

$$3x-6-2x=2$$

Combine $3x$ and $-2x$ to get $x$.

$$x-6=2$$

Add $6$ to both sides.

$$x=2+6$$

Add $2$ and $6$ to get $8$.

$$x=8$$

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Question

Solve for x

Steps for Solving Linear Equation