How to solve 3(x-5)+9 > 15

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(x-5)+9 > 15 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(x-5)+9 > 15$$

Solve for x

$x>7$

Solution Steps

Use the distributive property to multiply $3$ by $x-5$.

$$3x-15+9>15$$

Add $-15$ and $9$ to get $-6$.

$$3x-6>15$$

Add $6$ to both sides.

$$3x>15+6$$

Add $15$ and $6$ to get $21$.

$$3x>21$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$x>\frac{21}{3}$$

Divide $21$ by $3$ to get $7$.

$$x>7$$

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Solve for x

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