How to solve 3(x+3)(x-5)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(x+3)(x-5) | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(x+3)(x-5)$$

Evaluate

$3\left(x-5\right)\left(x+3\right)$

Solution Steps

Use the distributive property to multiply $3$ by $x+3$.

$$\left(3x+9\right)\left(x-5\right)$$

Apply the distributive property by multiplying each term of $3x+9$ by each term of $x-5$.

$$3x^{2}-15x+9x-45$$

Combine $-15x$ and $9x$ to get $-6x$.

$$3x^{2}-6x-45$$

Show Solution

Expand

$3x^{2}-6x-45$

Solution Steps

Use the distributive property to multiply $3$ by $x+3$.

$$\left(3x+9\right)\left(x-5\right)$$

Apply the distributive property by multiplying each term of $3x+9$ by each term of $x-5$.

$$3x^{2}-15x+9x-45$$

Combine $-15x$ and $9x$ to get $-6x$.

$$3x^{2}-6x-45$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Solution Steps

Expand

Solution Steps