How to solve 3(x+6)-40=6(x-3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(x+6)-40=6(x-3) | Equatix

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Question

$$3(x+6)-40=6(x-3)$$

Solve for x

$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $x+6$.

$$3x+18-40=6\left(x-3\right)$$

Subtract $40$ from $18$ to get $-22$.

$$3x-22=6\left(x-3\right)$$

Use the distributive property to multiply $6$ by $x-3$.

$$3x-22=6x-18$$

Subtract $6x$ from both sides.

$$3x-22-6x=-18$$

Combine $3x$ and $-6x$ to get $-3x$.

$$-3x-22=-18$$

Add $22$ to both sides.

$$-3x=-18+22$$

Add $-18$ and $22$ to get $4$.

$$-3x=4$$

Divide both sides by $-3$.

$$x=\frac{4}{-3}$$

Fraction $\frac{4}{-3}$ can be rewritten as $-\frac{4}{3}$ by extracting the negative sign.

$$x=-\frac{4}{3}$$

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