How to solve 3(y - 1) = 13 + y

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3(y - 1) = 13 + y | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3(y-1)=13+y$$

Solve for y

$y=8$

Steps for Solving Linear Equation

Use the distributive property to multiply $3$ by $y-1$.

$$3y-3=13+y$$

Subtract $y$ from both sides.

$$3y-3-y=13$$

Combine $3y$ and $-y$ to get $2y$.

$$2y-3=13$$

Add $3$ to both sides.

$$2y=13+3$$

Add $13$ and $3$ to get $16$.

$$2y=16$$

Divide both sides by $2$.

$$y=\frac{16}{2}$$

Divide $16$ by $2$ to get $8$.

$$y=8$$

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Question

Solve for y

Steps for Solving Linear Equation