Solve 3+{3-6-[9+12-(4+9)]} | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3+ \{ 3-6-[9+12-(4+9)] \}$$

Evaluate

$-8$

Solution Steps

Subtract $6$ from $3$ to get $-3$.

$$3+-3-\left(9+12-\left(4+9\right)\right)$$

Add $9$ and $12$ to get $21$.

$$3+-3-\left(21-\left(4+9\right)\right)$$

Add $4$ and $9$ to get $13$.

$$3+-3-\left(21-13\right)$$

Subtract $13$ from $21$ to get $8$.

$$3-3-8$$

Subtract $8$ from $-3$ to get $-11$.

$$3-11$$

Subtract $11$ from $3$ to get $-8$.

$$-8$$

Factor

$-8$