How to solve 3+(3)/(33)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3+(3)/(33) | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$3+ \frac{ 3 }{ 33 }$$

$\frac{34}{11}\approx 3.090909091$

Reduce the fraction $\frac{3}{33}$ to lowest terms by extracting and canceling out $3$.

$$3+\frac{1}{11}$$

Convert $3$ to fraction $\frac{33}{11}$.

$$\frac{33}{11}+\frac{1}{11}$$

Since $\frac{33}{11}$ and $\frac{1}{11}$ have the same denominator, add them by adding their numerators.

$$\frac{33+1}{11}$$

Add $33$ and $1$ to get $34$.

$$\frac{34}{11}$$

$\frac{2 \cdot 17}{11} = 3\frac{1}{11} = 3.090909090909091$