How to solve 3+(5)/(35)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3+(5)/(35) | Equatix

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$$3+ \frac{ 5 }{ 35 }$$

$\frac{22}{7}\approx 3.142857143$

Reduce the fraction $\frac{5}{35}$ to lowest terms by extracting and canceling out $5$.

$$3+\frac{1}{7}$$

Convert $3$ to fraction $\frac{21}{7}$.

$$\frac{21}{7}+\frac{1}{7}$$

Since $\frac{21}{7}$ and $\frac{1}{7}$ have the same denominator, add them by adding their numerators.

$$\frac{21+1}{7}$$

Add $21$ and $1$ to get $22$.

$$\frac{22}{7}$$

$\frac{2 \cdot 11}{7} = 3\frac{1}{7} = 3.142857142857143$