How to solve 3+(8)/(38)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3+(8)/(38) | Equatix

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$$3+ \frac{ 8 }{ 38 }$$

$\frac{61}{19}\approx 3.210526316$

Reduce the fraction $\frac{8}{38}$ to lowest terms by extracting and canceling out $2$.

$$3+\frac{4}{19}$$

Convert $3$ to fraction $\frac{57}{19}$.

$$\frac{57}{19}+\frac{4}{19}$$

Since $\frac{57}{19}$ and $\frac{4}{19}$ have the same denominator, add them by adding their numerators.

$$\frac{57+4}{19}$$

Add $57$ and $4$ to get $61$.

$$\frac{61}{19}$$

$\frac{61}{19} = 3\frac{4}{19} = 3.210526315789474$