Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$3 + \log _ { ( m + 1 ) } = \log _ { 3 } ( m + 1 )$$

Answer

$$C=(log(3,m+1)-log(m+1)^3)/3$$

Solution


Regroup terms.
\[3C+{\log{(m+1)}}^{3}=\log_{3}{(m+1)}\]
Subtract \({\log{(m+1)}}^{3}\) from both sides.
\[3C=\log_{3}{(m+1)}-{\log{(m+1)}}^{3}\]
Divide both sides by \(3\).
\[C=\frac{\log_{3}{(m+1)}-{\log{(m+1)}}^{3}}{3}\]
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