$$3^{4}-4^{3}\cdot(7^{2}-3\cdot4^{2})-4^{2}$$
$1$
$$81-4^{3}\left(7^{2}-3\times 4^{2}\right)-4^{2}$$
$$81-64\left(7^{2}-3\times 4^{2}\right)-4^{2}$$
$$81-64\left(49-3\times 4^{2}\right)-4^{2}$$
$$81-64\left(49-3\times 16\right)-4^{2}$$
$$81-64\left(49-48\right)-4^{2}$$
$$81-64\times 1-4^{2}$$
$$81-64-4^{2}$$
$$17-4^{2}$$
$$17-16$$
$$1$$
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