How to solve 3 ^ - 2 * 5 ^ - 3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 ^ - 2 * 5 ^ - 3 | Equatix

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$$3^{-2}\times5^{-3}$$

$\frac{1}{1125}\approx 0.000888889$

Calculate $3$ to the power of $-2$ and get $\frac{1}{9}$.

$$\frac{1}{9}\times 5^{-3}$$

Calculate $5$ to the power of $-3$ and get $\frac{1}{125}$.

$$\frac{1}{9}\times \frac{1}{125}$$

Multiply $\frac{1}{9}$ and $\frac{1}{125}$ to get $\frac{1}{1125}$.

$$\frac{1}{1125}$$

$\frac{1}{3 ^ {2} \cdot 5 ^ {3}} = 0.0008888888888888889$