Solve 3\times[(-2)\times5-(-10)\div(-5)]-(-4)=

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

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Question

$$3 \times [(-2) \times 5-(-10) \div (-5)]-(-4)=$$

Evaluate

$-32$

Solution Steps

Multiply $-2$ and $5$ to get $-10$.

$$3\left(-10-\frac{-10}{-5}\right)-\left(-4\right)$$

Divide $-10$ by $-5$ to get $2$.

$$3\left(-10-2\right)-\left(-4\right)$$

Subtract $2$ from $-10$ to get $-12$.

$$3\left(-12\right)-\left(-4\right)$$

Multiply $3$ and $-12$ to get $-36$.

$$-36-\left(-4\right)$$

The opposite of $-4$ is $4$.

$$-36+4$$

Add $-36$ and $4$ to get $-32$.

$$-32$$

Show Solution

Factor

$-32$

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