$$3 \times \sqrt{ 49 } -2 \times \sqrt{ 36 } +4 \times \sqrt{ 25 } =$$
$29$
$$3\times 7-2\sqrt{36}+4\sqrt{25}$$
$$21-2\sqrt{36}+4\sqrt{25}$$
$$21-2\times 6+4\sqrt{25}$$
$$21-12+4\sqrt{25}$$
$$9+4\sqrt{25}$$
$$9+4\times 5$$
$$9+20$$
$$29$$
Show Solution
Hide Solution