How to solve 3 imes2+6-4-(4-0)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3\times2+6-4-(4-0) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3 \times 2+6-4-(4-0)$$

Evaluate

$4$

Solution Steps

Multiply $3$ and $2$ to get $6$.

$$6+6-4-\left(4-0\right)$$

Add $6$ and $6$ to get $12$.

$$12-4-\left(4-0\right)$$

Subtract $4$ from $12$ to get $8$.

$$8-\left(4-0\right)$$

Subtract $0$ from $4$ to get $4$.

$$8-4$$

Subtract $4$ from $8$ to get $4$.

$$4$$

Show Solution

Factor

$2^{2}$

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