$$3 \times 9[(6+16-8)-12 \div 4]=$$
$297$
$$27\left(6+16-8-\frac{12}{4}\right)$$
$$27\left(22-8-\frac{12}{4}\right)$$
$$27\left(14-\frac{12}{4}\right)$$
$$27\left(14-3\right)$$
$$27\times 11$$
$$297$$
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$3^{3}\times 11$
